The Natural Logarithm and the Number e

April 12, 2026

Problem

Show that lim(n→∞) (1+1/n)^n = e ≈ 2.718. Animate the value converging.

Explanation

What is ee?

Euler's number e≈2.71828...e \approx 2.71828... is one of the most important constants in mathematics. It's defined as:

e=lim⁡n→∞(1+1n)ne = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n

Step-by-step: watching convergence

Compute (1+1n)n\left(1 + \frac{1}{n}\right)^n for increasing nn:

  • n=1n = 1: (1+1)1=2.000(1 + 1)^1 = 2.000
  • n=2n = 2: (1.5)2=2.250(1.5)^2 = 2.250
  • n=5n = 5: (1.2)5=2.488(1.2)^5 = 2.488
  • n=10n = 10: (1.1)10=2.594(1.1)^{10} = 2.594
  • n=100n = 100: (1.01)100=2.705(1.01)^{100} = 2.705
  • n=1000n = 1000: (1.001)1000=2.717(1.001)^{1000} = 2.717
  • n=10000n = 10000: (1.0001)10000=2.71815(1.0001)^{10000} = 2.71815

The values settle down to e=2.71828...e = 2.71828...

Where ee comes from: compound interest

If you invest $1 at 100% annual interest compounded nn times per year, after 1 year you have (1+1/n)n(1 + 1/n)^n dollars. With continuous compounding (n→∞n \to \infty), you get exactly ee dollars. This is why ee appears in finance, biology (population growth), physics (radioactive decay), and everywhere exponential change occurs.

The natural logarithm

ln⁡x=log⁡ex\ln x = \log_e x is the logarithm with base ee. It's "natural" because ddx[ln⁡x]=1x\frac{d}{dx}[\ln x] = \frac{1}{x} — the simplest possible derivative for a log function.

Key values: ln⁡1=0\ln 1 = 0, ln⁡e=1\ln e = 1, ln⁡e2=2\ln e^2 = 2.

Try it in the visualization

Watch (1+1/n)n(1 + 1/n)^n converge as nn increases. The graph shows the value approaching the ee reference line. A table displays the sequence of values.

Interactive Visualization

Parameters

10.00
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