The Natural Logarithm and the Number e

April 12, 2026

Problem

Show that lim(n→∞) (1+1/n)^n = e ≈ 2.718. Animate the value converging.

Explanation

What is ee?

Euler's number e2.71828...e \approx 2.71828... is one of the most important constants in mathematics. It's defined as:

e=limn(1+1n)ne = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n

Step-by-step: watching convergence

Compute (1+1n)n\left(1 + \frac{1}{n}\right)^n for increasing nn:

  • n=1n = 1: (1+1)1=2.000(1 + 1)^1 = 2.000
  • n=2n = 2: (1.5)2=2.250(1.5)^2 = 2.250
  • n=5n = 5: (1.2)5=2.488(1.2)^5 = 2.488
  • n=10n = 10: (1.1)10=2.594(1.1)^{10} = 2.594
  • n=100n = 100: (1.01)100=2.705(1.01)^{100} = 2.705
  • n=1000n = 1000: (1.001)1000=2.717(1.001)^{1000} = 2.717
  • n=10000n = 10000: (1.0001)10000=2.71815(1.0001)^{10000} = 2.71815

The values settle down to e=2.71828...e = 2.71828...

Where ee comes from: compound interest

If you invest $1 at 100% annual interest compounded nn times per year, after 1 year you have (1+1/n)n(1 + 1/n)^n dollars. With continuous compounding (nn \to \infty), you get exactly ee dollars. This is why ee appears in finance, biology (population growth), physics (radioactive decay), and everywhere exponential change occurs.

The natural logarithm

lnx=logex\ln x = \log_e x is the logarithm with base ee. It's "natural" because ddx[lnx]=1x\frac{d}{dx}[\ln x] = \frac{1}{x} — the simplest possible derivative for a log function.

Key values: ln1=0\ln 1 = 0, lne=1\ln e = 1, lne2=2\ln e^2 = 2.

Try it in the visualization

Watch (1+1/n)n(1 + 1/n)^n converge as nn increases. The graph shows the value approaching the ee reference line. A table displays the sequence of values.

Interactive Visualization

Parameters

10.00
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The Natural Logarithm and the Number e | MathSpin