Sum of an Infinite Geometric Series

April 12, 2026

Problem

Find 1+1/3+1/9+1/27+... = 1/(1−1/3) = 3/2.

Explanation

Can an infinite sum be finite?

Yes! If each term is a fixed fraction of the previous one, and that fraction r|r| is less than 1, the terms shrink so fast that their infinite sum converges to a finite number.

The formula

For an infinite geometric series with first term a1a_1 and common ratio r<1|r| < 1:

S=a11rS_\infty = \frac{a_1}{1 - r}

If r1|r| \geq 1, the series diverges (sum is infinite).

Step-by-step: Find 1+13+19+127+1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \cdots

Step 1 — Identify a1a_1 and rr.

a1=1a_1 = 1. Common ratio: r=1/31=13r = \frac{1/3}{1} = \frac{1}{3}.

Step 2 — Check convergence. r=1/3<1|r| = 1/3 < 1 ✓ (the series converges).

Step 3 — Apply the formula:

S=111/3=12/3=32=1.5S = \frac{1}{1 - 1/3} = \frac{1}{2/3} = \frac{3}{2} = 1.5

Step 4 — Verify with partial sums:

S1=1S_1 = 1, S2=1.333S_2 = 1.333, S3=1.444S_3 = 1.444, S4=1.481S_4 = 1.481, S5=1.494S_5 = 1.494, ... approaching 1.51.5 ✓.

Why it works intuitively

Each term adds less than the previous: 1,0.333,0.111,0.037,1, 0.333, 0.111, 0.037, \ldots The amounts shrink so fast that even adding infinitely many of them can't exceed 3/23/2.

Common exam variations

  • Repeating decimals: 0.333=3/10+3/100+3/1000+=3/1011/10=130.333\ldots = 3/10 + 3/100 + 3/1000 + \cdots = \frac{3/10}{1 - 1/10} = \frac{1}{3}.
  • Bouncing ball: A ball dropped from height hh bounces to rhrh each time. Total distance = h+2hr1rh + 2h \cdot \frac{r}{1-r}.

Try it in the visualization

Adjust a1a_1 and rr. Watch the shrinking bars accumulate. The convergence graph shows partial sums approaching the limit. The limit line confirms the formula's prediction.

Interactive Visualization

Parameters

1.00
0.33
10.00
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