Solving Absolute Value Equations

April 12, 2026

Problem

Solve |2x−3| = 7. Two cases: 2x−3 = 7 or 2x−3 = −7.

Explanation

How to solve absolute value equations

The absolute value ∣A∣|A| equals cc means AA is either +c+c or −c-c. So ∣A∣=c|A| = c splits into two separate equations: A=cA = c or A=−cA = -c. Solve each one independently, then check both answers.

Important: If c<0c < 0, there is no solution — absolute value is never negative.

Step-by-step solution: Solve ∣2x−3∣=7|2x - 3| = 7

Step 1 — Check that the right side is non-negative. 7≥07 \geq 0 ✓, so solutions may exist.

Step 2 — Set up two cases:

Case 1: 2x−3=72x - 3 = 7

2x=102x = 10 x=5x = 5

Case 2: 2x−3=−72x - 3 = -7

2x=−42x = -4 x=−2x = -2

Step 3 — Check both solutions in the original equation.

  • x=5x = 5: ∣2(5)−3∣=∣10−3∣=∣7∣=7|2(5) - 3| = |10 - 3| = |7| = 7 ✓
  • x=−2x = -2: ∣2(−2)−3∣=∣−4−3∣=∣−7∣=7|2(-2) - 3| = |-4 - 3| = |-7| = 7 ✓

Solution: x=5x = 5 or x=−2x = -2.

Graphical interpretation

The graph of y=∣2x−3∣y = |2x - 3| is a V-shape with vertex at x=3/2x = 3/2. The horizontal line y=7y = 7 intersects the V at two points — those x-coordinates are the two solutions.

Common mistakes

  • Forgetting the negative case. ∣A∣=7|A| = 7 gives TWO equations, not one.
  • Writing ∣A∣=−5|A| = -5 and trying to solve. No solution exists — absolute value is always ≥0\geq 0.
  • Not checking for extraneous solutions when the equation is more complex (e.g., ∣x−1∣=2x+3|x - 1| = 2x + 3 — the negative case can produce extraneous roots).

Try it in the visualization

Adjust aa, bb, cc in ∣ax+b∣=c|ax + b| = c. The V-shaped graph and horizontal line y=cy = c are drawn — intersections are the solutions. Set c<0c < 0 to see "no solution."

Interactive Visualization

Parameters

2.00
-3.00
7.00
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Solving Absolute Value Equations | MathSpin