Relative Motion of Two Cars: Constant Speed vs Constant Acceleration

March 26, 2026

Problem

A car A is moving at 20 m/s. Another car B starts from rest at the same point and accelerates at 4 m/s².

Explanation

We compare the motion of two cars starting from the same point:

  • Car A moves with constant velocity vA=20m/sv_A = 20\,\text{m/s}.
  • Car B starts from rest with constant acceleration aB=4m/s2a_B = 4\,\text{m/s}^2.

We use the standard kinematic equations (with tt in seconds, xx in meters):

  1. Car A (constant speed)

    • Initial position: xA0=0x_{A0} = 0
    • Initial velocity: vA=20m/sv_A = 20\,\text{m/s}
    • Acceleration: aA=0a_A = 0

    Position as a function of time:

xA(t)=xA0+vAt=20tx_A(t) = x_{A0} + v_A t = 20 t
  1. Car B (starting from rest, constant acceleration)

    • Initial position: xB0=0x_{B0} = 0
    • Initial velocity: vB0=0v_{B0} = 0
    • Acceleration: aB=4m/s2a_B = 4\,\text{m/s}^2

    Position:

xB(t)=xB0+vB0t+12aBt2=2t2x_B(t) = x_{B0} + v_{B0} t + \tfrac12 a_B t^2 = 2 t^2
  1. When does car B catch car A?

We set the positions equal:

xA(t)=xB(t)20t=2t2x_A(t) = x_B(t) \quad \Rightarrow \quad 20t = 2 t^2

Rearrange:

2t220t=02t(t10)=02t^2 - 20t = 0 \quad \Rightarrow \quad 2t(t - 10) = 0

So either t=0t = 0 (the start) or t=10t = 10 s. The non-trivial solution is:

tmeet=10st_{\text{meet}} = 10\,\text{s}

The meeting position:

xA(10)=2010=200mxB(10)=2102=200mx_A(10) = 20 \cdot 10 = 200\,\text{m}\\ x_B(10) = 2 \cdot 10^2 = 200\,\text{m}

Both cars are 200 m from the start at t=10t = 10 s.

  1. Interpretation
  • Initially, car A pulls ahead with its constant speed.
  • Car B starts slowly but speeds up because of its acceleration.
  • After around 10 seconds, car B's increasing speed allows it to catch up with car A.
  1. What this visualization shows

The canvas shows a 1D motion diagram along a horizontal road:

  • A dark background for contrast.
  • Car A (cyan) moves at constant speed.
  • Car B (pink) starts at rest and accelerates.
  • A vertical neon line marks the meeting point where their positions are equal.
  • A time slider and play speed let you explore the motion before and after they meet.
  • Optional toggles let you display the trajectory curves xA(t)x_A(t) and xB(t)x_B(t) in a mini graph area, so you can see where the curves intersect at t=10t=10 s.

You can also adjust the speeds and acceleration in the widgets to see how the meeting time and distance change, turning this into a general tool for constant-speed vs constant-acceleration comparisons.

Interactive Visualization

Parameters

20.00
4.00
15.00
1.00
Relative Motion of Two Cars: Constant Speed vs Constant Acceleration