Power = Work / Time
Problem
A motor lifts 100 kg by 10 m in 5 seconds. Calculate the average power.
Explanation
Power measures how fast work is being done — it's the rate of energy transfer. Two motors can do the same total work, but the more powerful one does it in less time.
The Formula
Units: 1 watt = 1 joule per second. Other common units: 1 horsepower ≈ 745.7 watts.
Step-by-Step Solution
Given: lifted by in , .
Find: The average power .
Step 1 — Compute the work done.
Lifting the mass by at constant speed (or with no net acceleration at the end) requires work equal to the gain in gravitational potential energy:
Step 2 — Divide by time.
Step 3 — Convert to horsepower for intuition.
So the motor outputs about 2.6 horsepower to lift 100 kg by 10 m in 5 seconds. That's roughly the power of a high-end electric scooter motor or a strong human athlete sprinting.
Step 4 — What if it took half as long?
If the same lift happened in 2.5 seconds instead:
Same energy, doubled rate, doubled power. Power and time are inversely proportional for a fixed amount of work.
Step 5 — How does power relate to force and velocity?
For an object moving at speed being pushed by force in the direction of motion:
This is the instantaneous power. For the motor lifting at constant speed with the lifting force :
Both methods agree.
Answer:
The motor delivers an average of 1962 watts (about 2.6 horsepower) to lift 100 kg by 10 meters in 5 seconds.
Try It
- Adjust the mass, height, and time sliders.
- Notice that doubling the time halves the power (same work, slower delivery).
- Watch the elevator visualization rise faster or slower as you change the time.
- The HUD shows both the work and the resulting power in watts and horsepower.
Interactive Visualization
Parameters
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