Power = Work / Time

April 12, 2026

Problem

A motor lifts 100 kg by 10 m in 5 seconds. Calculate the average power.

Explanation

Power measures how fast work is being done — it's the rate of energy transfer. Two motors can do the same total work, but the more powerful one does it in less time.

The Formula

P=Wt=work donetime takenP = \dfrac{W}{t} = \dfrac{\text{work done}}{\text{time taken}}

Units: 1 watt = 1 joule per second. Other common units: 1 horsepower ≈ 745.7 watts.

Step-by-Step Solution

Given: m=100  kgm = 100\;\text{kg} lifted by h=10  mh = 10\;\text{m} in t=5  st = 5\;\text{s}, g=9.81  m/s2g = 9.81\;\text{m/s}^{2}.

Find: The average power PP.


Step 1 — Compute the work done.

Lifting the mass by hh at constant speed (or with no net acceleration at the end) requires work equal to the gain in gravitational potential energy:

W=mgh=(100)(9.81)(10)=9810  JW = mgh = (100)(9.81)(10) = 9810\;\text{J}

Step 2 — Divide by time.

P=Wt=98105=1962  WP = \dfrac{W}{t} = \dfrac{9810}{5} = 1962\;\text{W}

Step 3 — Convert to horsepower for intuition.

P=1962745.72.63  hpP = \dfrac{1962}{745.7} \approx 2.63\;\text{hp}

So the motor outputs about 2.6 horsepower to lift 100 kg by 10 m in 5 seconds. That's roughly the power of a high-end electric scooter motor or a strong human athlete sprinting.

Step 4 — What if it took half as long?

If the same lift happened in 2.5 seconds instead:

P=98102.5=3924  W5.26  hpP = \dfrac{9810}{2.5} = 3924\;\text{W} \approx 5.26\;\text{hp}

Same energy, doubled rate, doubled power. Power and time are inversely proportional for a fixed amount of work.

Step 5 — How does power relate to force and velocity?

For an object moving at speed vv being pushed by force FF in the direction of motion:

P=FvP = F\,v

This is the instantaneous power. For the motor lifting at constant speed v=10/5=2  m/sv = 10/5 = 2\;\text{m/s} with the lifting force F=mg=981  NF = mg = 981\;\text{N}:

P=(981)(2)=1962  W    P = (981)(2) = 1962\;\text{W} \;\;\checkmark

Both methods agree.


Answer:

  P=Wt=mght=1962  W2.63  hp  \boxed{\;P = \dfrac{W}{t} = \dfrac{mgh}{t} = 1962\;\text{W} \approx 2.63\;\text{hp}\;}

The motor delivers an average of 1962 watts (about 2.6 horsepower) to lift 100 kg by 10 meters in 5 seconds.

Try It

  • Adjust the mass, height, and time sliders.
  • Notice that doubling the time halves the power (same work, slower delivery).
  • Watch the elevator visualization rise faster or slower as you change the time.
  • The HUD shows both the work and the resulting power in watts and horsepower.

Interactive Visualization

Parameters

100.00
10.00
5.00
Your turn

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Power = Work / Time | MathSpin