Parametric Equations: Projectile Motion

April 12, 2026

Problem

Plot x(t) = v₀ cos(θ) · t and y(t) = v₀ sin(θ) · t − ½gt² as a parametric curve. Show how the parameter t maps to position along the trajectory, with x(t) and y(t) displayed as separate time-domain graphs alongside the spatial path.

Explanation

Parametric equations express both xx and yy as functions of a third variable — a parameter, usually time tt. Instead of y=f(x)y = f(x), we have x=f(t)x = f(t) and y=g(t)y = g(t). As tt advances, the point (x(t),y(t))(x(t), y(t)) traces a curve in the xyxy-plane.

Projectile motion is the classic example: x(t)=v0cosθtx(t) = v_{0}\cos\theta \cdot t (constant horizontal velocity) and y(t)=v0sinθt12gt2y(t) = v_{0}\sin\theta \cdot t - \frac{1}{2}gt^{2} (vertical: upward velocity minus gravity).

With v0=20v_{0} = 20 m/s and θ=45°\theta = 45°: x(t)=14.14tx(t) = 14.14t, y(t)=14.14t4.9t2y(t) = 14.14t - 4.9t^{2}. The projectile lands at t=2.89t = 2.89 s, having traveled x=40.8x = 40.8 m.

Why parametric?

The parametric form captures when the projectile is at each position, not just where the curve goes. Two projectiles can follow the same parabolic path at different speeds — same curve, different parametrizations.

Try it in the visualization

Watch the projectile trace its parabolic arc as tt advances. The two smaller graphs show x(t)x(t) (linear) and y(t)y(t) (quadratic) separately. Adjust initial speed and angle to change the trajectory. The time slider lets you freeze at any instant.

Interactive Visualization

Parameters

20.00
45.00
9.80
Your turn

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Parametric Equations: Projectile Motion | MathSpin