Normal Distribution: The Bell Curve and 68-95-99.7 Rule

April 12, 2026

Problem

Show the standard normal distribution N(μ, σ) with the 68-95-99.7 rule: 68% of data falls within 1σ of the mean, 95% within 2σ, and 99.7% within 3σ. Adjust μ and σ to see how the curve shifts and spreads.

Explanation

The normal distribution (Gaussian distribution) is the most important probability distribution in statistics. It describes countless natural phenomena — heights, test scores, measurement errors, blood pressure — because of the Central Limit Theorem.

The probability density function is:

f(x)=1σ2πe(xμ)22σ2f(x) = \dfrac{1}{\sigma\sqrt{2\pi}} e^{-\frac{(x-\mu)^{2}}{2\sigma^{2}}}

The 68-95-99.7 (empirical) rule

  • 68% of data falls within 1 standard deviation of the mean (μ±σ\mu \pm \sigma)
  • 95% within 2 standard deviations (μ±2σ\mu \pm 2\sigma)
  • 99.7% within 3 standard deviations (μ±3σ\mu \pm 3\sigma)

This means if test scores have μ=75\mu = 75, σ=10\sigma = 10: about 68% score between 65 and 85, 95% between 55 and 95, and 99.7% between 45 and 105.

Try it in the visualization

Adjust μ\mu (shifts the center) and σ\sigma (controls width — smaller σ = taller, narrower; larger σ = shorter, wider). Toggle the 68/95/99.7 shading to see the area fractions. The total area under the curve is always 1 (100%).

Interactive Visualization

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Normal Distribution: The Bell Curve and 68-95-99.7 Rule | MathSpin