Margin of Error in Polls

April 12, 2026

Problem

In a poll of 1000 people, 52% support a proposal. Find the margin of error at 95% confidence.

Explanation

What is margin of error?

The margin of error (MOE) is the "±" in poll results: "52% ± 3.1% support the proposal." It defines the width of the confidence interval.

MOE=zp^(1p^)nMOE = z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

Step-by-step

Given: p^=0.52\hat{p} = 0.52, n=1000n = 1000, 95% confidence (z=1.96z^* = 1.96).

Step 1 — Standard error of proportion:

SE=0.52×0.481000=0.24961000=0.0002496=0.01580SE = \sqrt{\frac{0.52 \times 0.48}{1000}} = \sqrt{\frac{0.2496}{1000}} = \sqrt{0.0002496} = 0.01580

Step 2 — Margin of error:

MOE=1.96×0.01580=0.0310=3.1%MOE = 1.96 \times 0.01580 = 0.0310 = 3.1\%

Step 3 — Confidence interval: 52%±3.1%=(48.9%,55.1%)52\% \pm 3.1\% = (48.9\%, 55.1\%)

Interpretation

We're 95% confident that the true population support is between 48.9% and 55.1%. Since this range includes 50%, we cannot conclude the proposal has majority support with 95% confidence.

How to reduce MOE

  • Increase sample size: n=4000n = 4000 would cut MOE in half.
  • Accept lower confidence: 90% CI has smaller MOE than 95%.

Try it in the visualization

Enter poll results. The MOE is computed and shown as an interval. Adjust nn to see the MOE shrink. The 50% line shows whether the result is statistically significant.

Interactive Visualization

Parameters

52.00
1000.00
95%
Your turn

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Margin of Error in Polls | MathSpin