Coulomb’s Law: Inverse-Square Electrostatic Force

April 26, 2026

Problem

Derive Coulomb's law as given in the attached image.

Explanation

Coulomb’s Law

The electrostatic force between two point charges is

F=14πϵ0q1q2r2F=\frac{1}{4\pi\epsilon_0}\frac{q_1 q_2}{r^2}

where:

  • q1q_1 and q2q_2 are the charges,
  • rr is the distance between them,
  • ϵ0\epsilon_0 is the permittivity of free space.

How this form arises

The law can be understood from two key experimental facts:

  1. Dependence on charge: the force increases proportionally with the amount of charge on each body.
  2. Inverse-square dependence on distance: when the separation doubles, the force becomes one-fourth as large.

These observations combine into

Fq1q2r2F \propto \frac{q_1 q_2}{r^2}

To turn this proportionality into an equation, we introduce a constant of proportionality:

F=kq1q2r2F = k\frac{q_1 q_2}{r^2}

In SI units, this constant is

k=14πϵ0k = \frac{1}{4\pi\epsilon_0}

so the final result becomes

F=14πϵ0q1q2r2F=\frac{1}{4\pi\epsilon_0}\frac{q_1 q_2}{r^2}

Interpretation

  • If q1q2>0q_1 q_2 > 0, the force is repulsive.
  • If q1q2<0q_1 q_2 < 0, the force is attractive.
  • The force acts along the line joining the two charges.

Visual meaning

This visualization shows two charges and the force between them. You can change:

  • the value of the charges,
  • their separation,
  • whether they attract or repel.

As distance increases, the force arrows shrink rapidly according to the inverse-square law.

Interactive Visualization

Parameters

4.00
-4.00
5.00
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Coulomb’s Law: Inverse-Square Electrostatic Force | MathSpin