Continuous Compounding: A = Pe^(rt)

April 13, 2026

Problem

Compare discrete compounding A = P(1 + r/n)^(nt) with continuous A = Pe^(rt) for $1,000 at 10% for 5 years, as n increases.

Explanation

The idea

Compounding more frequently gives more growth, but the gain flattens out as nn \to \infty. The limit is continuous compounding: A=PertA = P e^{rt}

where e2.71828e \approx 2.71828 is Euler's number. This is the theoretical "max speed" for a given annual rate.

Why the limit is erte^{rt}

Start from discrete compounding A=P(1+r/n)ntA = P (1 + r/n)^{nt}. Let m=n/rm = n/r, so r/n=1/mr/n = 1/m and nt=mrtnt = mrt: A=P[(1+1m)m]rtA = P\left[\left(1 + \dfrac{1}{m}\right)^m\right]^{rt}

As nn \to \infty, mm \to \infty, and (1+1m)me\left(1 + \dfrac{1}{m}\right)^m \to e. So APertA \to P e^{rt}.

Step-by-step comparison

Setup: P=1000P = 1000, r=0.10r = 0.10, t=5t = 5.

Compute for several nn:

Annually (n=1n = 1): A=1000(1.10)5=1610.51A = 1000 \cdot (1.10)^5 = 1610.51

Quarterly (n=4n = 4): A=1000(1.025)20=1638.62A = 1000 \cdot (1.025)^{20} = 1638.62

Monthly (n=12n = 12): A=1000(1.00833)601645.31A = 1000 \cdot (1.00833)^{60} \approx 1645.31

Daily (n=365n = 365): A=1000(1+0.10/365)18251648.66A = 1000 \cdot (1 + 0.10/365)^{1825} \approx 1648.66

Continuous: A=1000e0.51648.72A = 1000 \cdot e^{0.5} \approx \boxed{1648.72}

The jump from annual to daily is ~38;thejumpfromdailytocontinuousisonly 38; the jump from daily to continuous is only ~0.06. The curve flattens fast past daily.

Rearrangements

Given any three of A,P,r,tA, P, r, t you can solve for the fourth:

  • P=AertP = A e^{-rt} (present value)
  • t=ln(A/P)rt = \dfrac{\ln(A/P)}{r} (time to a target)
  • r=ln(A/P)tr = \dfrac{\ln(A/P)}{t} (required rate)

These are the log-rate versions, convenient for analytical work.

Where continuous compounding lives

  • Derivative pricing (Black–Scholes, options): quote rates as continuously compounded.
  • Physics-style growth/decay: radioactive decay, population models, Newton's law of cooling.
  • Effective-rate conversions: convert any compounding convention to continuous and back.

Converting between conventions

Discrete nominal rate rnr_n compounded nn times per year ⟷ continuous rate rcr_c: rc=nln(1+rn/n)r_c = n \ln(1 + r_n/n) rn=n(erc/n1)r_n = n\left(e^{r_c/n} - 1\right)

For small rates these are nearly equal; for large rates they diverge meaningfully.

Common mistakes

  • Using ere^r instead of erte^{rt}. The exponent is the rate times time, not the rate alone.
  • Confusing continuous rates with APY. APY = effective annual yield; continuous rate is a different convention, related by APY=erc1APY = e^{r_c} - 1.
  • Thinking continuous always crushes monthly. Over a 30-year horizon at 6%, monthly \approx continuous to within 0.1%. The extra is often negligible.

Try it in the visualization

A growth-factor curve shows (1+r/n)nt(1 + r/n)^{nt} approaching erte^{rt} from below as nn increases. A side panel prints the dollar values so you can see the shrinking gap.

Interactive Visualization

Parameters

1000.00
10.00
5.00
12.00
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Continuous Compounding: A = Pe^(rt) | MathSpin