Circle Circumference: C = 2πr

April 12, 2026

Problem

Show that a circle's circumference is 2π times its radius by "unrolling" the circle into a straight line.

Explanation

The circumference of a circle is famously C=2πrC = 2\pi r (or equivalently C=πdC = \pi d, where dd is the diameter). The constant π3.14159\pi \approx 3.14159 shows up because every circle has the same ratio of circumference to diameter — that ratio defines π\pi.

The Definition of π

For any circle:

π=Cd=C2r\pi = \dfrac{C}{d} = \dfrac{C}{2r}

So C=2πrC = 2\pi r. This isn't a derivation — it's literally the definition of π\pi. Geometrically, π\pi is "how many diameters' worth of arc you wrap around to get back where you started."

Step-by-Step Solution

Given: A circle of radius r=1r = 1.

Find: The circumference, and verify by approximating with inscribed polygons.


Step 1 — Apply the formula.

C=2πr=2π(1)=2π6.2832C = 2\pi r = 2\pi(1) = 2\pi \approx 6.2832

Step 2 — Approximate by inscribing regular polygons.

The circumference of a regular nn-sided polygon inscribed in a unit circle is:

Cn=2nsin ⁣(πn)C_n = 2n\sin\!\left(\dfrac{\pi}{n}\right)

(Each side is the chord of an angle 2π/n2\pi/n; using the chord length formula gives 2sin(π/n)2\sin(\pi/n).)

Tabulate for several nn:

  • n=4n = 4 (square): C4=8sin(π/4)5.657C_4 = 8\sin(\pi/4) \approx 5.657
  • n=6n = 6 (hexagon): C6=12sin(π/6)=6.000C_6 = 12\sin(\pi/6) = 6.000
  • n=12n = 12: C12=24sin(π/12)6.211C_{12} = 24\sin(\pi/12) \approx 6.211
  • n=24n = 24: C246.265C_{24} \approx 6.265
  • n=48n = 48: C486.279C_{48} \approx 6.279
  • n=100n = 100: C1006.282C_{100} \approx 6.282
  • nn \to \infty: Cn2π6.283C_n \to 2\pi \approx 6.283

This is exactly how Archimedes computed π\pi around 250 BC, eventually getting it to 3.1408<π<3.14293.1408 < \pi < 3.1429 using a 96-sided polygon.

Step 3 — Verify the approximation rate.

The polygon underestimates the circle (chord length is less than arc length). The error shrinks as 1/n21/n^{2}, so each doubling of nn gives 4× the accuracy.

Step 4 — Compute for some real-world examples.

  • A bicycle wheel of radius r=0.35  mr = 0.35\;\text{m}: C=2π(0.35)2.199  mC = 2\pi(0.35) \approx 2.199\;\text{m} — that's how far you go per revolution.
  • The Earth's equator (radius 6378  km\approx 6378\;\text{km}): C40,075  kmC \approx 40{,}075\;\text{km}.
  • An atomic nucleus (radius 1015  m\sim 10^{-15}\;\text{m}): C6×1015  mC \sim 6 \times 10^{-15}\;\text{m}.

Answer:

  C=2πr=2π6.2832  \boxed{\;C = 2\pi r = 2\pi \approx 6.2832\;}

For any circle, the circumference is exactly 2π2\pi times the radius — that ratio is what π\pi means. As you inscribe polygons with more and more sides, their perimeters converge to this value.

Try It

  • Adjust the number of polygon sides to see how quickly the polygon perimeter approaches the true circumference.
  • Watch the polygon "round out" into a circle as nn grows.
  • At n=100n = 100, the polygon is visually indistinguishable from the circle.

Interactive Visualization

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Circle Circumference: C = 2πr | MathSpin